A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1 x 10^5 gallons of water. How many tetras can it house? Write the answer in scientific notation. (1 point)
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To find out how many neon tetras can be housed in the aquarium, we need to divide the total volume of water in the aquarium by the volume of water needed per neon tetra.
The volume of water in the aquarium is given as 1 x 10^5 gallons.
The volume of water needed per neon tetra is 1.25 gallons.
Dividing the total volume of water in the aquarium by the volume of water needed per neon tetra gives:
(1 x 10^5 gallons) / (1.25 gallons) = 8 x 10^4 tetras
Therefore, the public aquarium can house 8 x 10^4 tetras.
To determine how many tetras the aquarium can house, we divide the total volume of water in the aquarium by the amount of water each tetra needs.
The total volume of water in the aquarium is given as 1 x 10^5 gallons.
Each neon tetra needs 1.25 gallons of water.
Therefore, we divide the total volume of water by the amount needed per tetra:
(1 x 10^5 gallons) / (1.25 gallons/tetra)
Simplifying this expression, we have:
(1 x 10^5) / (1.25)
Dividing 1 x 10^5 by 1.25 gives us:
8 x 10^4
So, the aquarium can house 8 x 10^4 tetras.
To find out how many tetras can be housed in the aquarium, we need to divide the total volume of water in the aquarium by the amount of water required for each tetra.
First, let's calculate the number of tetras by dividing the total volume of water by the water required for each tetra:
Number of tetras = Total volume of water / Water required per tetra
Number of tetras = 1 x 10^5 gallons / 1.25 gallons
Now, divide the two numbers to get the answer.
Number of tetras = 8 x 10^4 tetras
Therefore, the aquarium can house 8 x 10^4 (or 80,000) tetras.
Please note that scientific notation is used to express very large or very small numbers in a more compact form. In scientific notation, the number 8 x 10^4 represents 8 multiplied by 10 raised to the power of 4.