A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground the squirrel moves from the perch down to its stored acorns in 5.2 five seconds interpret the quotient to describe the rate of change in the scrolls height above the ground, give your answer to the nearest hundredth
The rate of change in the squirrel's height above the ground can be described by the quotient of the change in height divided by the time it takes to move.
The squirrel starts on a perch 100 feet above the ground and moves down to its stored acorns, which are 45 feet from the ground.
The change in height is 100 feet - 45 feet = 55 feet.
The time it takes to move is 5.2 seconds.
Therefore, the rate of change in the squirrel's height above the ground is 55 feet / 5.2 seconds ≈ 10.58 feet/second (rounded to the nearest hundredth).
To find the rate of change in the squirrel's height, we need to calculate the difference in height divided by the time taken.
The squirrel starts on a perch 100 feet above the ground and moves down to its stored acorns, which are 45 feet from the ground. So the difference in height is 100 - 45 = 55 feet.
The time taken is 5.2 seconds.
Now, we can calculate the rate of change by dividing the height difference by the time taken:
Rate of change = Height difference / Time taken
Rate of change = 55 feet / 5.2 seconds
Calculating this value, we get:
Rate of change ≈ 10.58 feet per second (rounded to the nearest hundredth)
Therefore, the squirrel descends at a rate of approximately 10.58 feet per second.
To find the rate of change in the squirrel's height above the ground, we need to calculate the change in height divided by the time it took.
The initial height of the squirrel is 100 feet above the ground, and it moves down to its stored acorns, which are 45 feet above the ground. So, the change in height is 100 - 45 = 55 feet.
The time it took for the squirrel to move is given as 5.2 seconds.
Now, to find the rate of change, we divide the change in height by the time taken:
Rate of change = Change in height / Time taken = 55 feet / 5.2 seconds
Calculating this, we get:
Rate of change ≈ 10.58 feet/second
Therefore, the rate of change in the squirrel's height above the ground is approximately 10.58 feet per second.