Bot a squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel's height above the ground. Give your answer to the nearest hundredth. Pick one of these answers. the quotient that describes the rate of change in the squirrel's height above the ground is 19.05 feet/second. the quotient that describes the rate of changes in the squirrel's height above ground is -10.48 feet/second. the quotient that describes the rate of change in the squirrel's height above ground is -19.05 feet/second. the quotient that describes the rate of change in the squirrel's height above ground is 10.48 feet/second.
To find the rate of change in the squirrel's height above the ground, we divide the change in height by the time it took for the squirrel to move.
Change in height = 100 feet - 45 feet = 55 feet
Time = 5.25 seconds
Rate of change = Change in height / Time
Rate of change = 55 feet / 5.25 seconds ≈ 10.48 feet/second
Therefore, the quotient that describes the rate of change in the squirrel's height above the ground is 10.48 feet/second.
To find the rate of change in the squirrel's height above the ground, we divide the change in height by the time it takes.
The squirrel starts at a height of 100 feet and moves down to a height of 45 feet, which is a change of 100 - 45 = 55 feet.
The time it takes for the squirrel to make this change is given as 5.25 seconds.
To calculate the rate of change, we divide the change in height by the time:
Rate of change = Change in height / Time = 55 feet / 5.25 seconds.
Calculating this quotient gives us approximately 10.48 feet/second.
So, the correct answer is: the quotient that describes the rate of change in the squirrel's height above the ground is 10.48 feet/second.
To find the rate of change in the squirrel's height above the ground, we need to divide the change in height by the change in time.
The squirrel starts on a perch 100 feet above the ground and moves down to the hole that is 45 feet above the ground. Therefore, the change in height is 100 feet - 45 feet = 55 feet.
The squirrel takes 5.25 seconds to make this change in height, so the change in time is 5.25 seconds.
To find the rate of change, we divide the change in height by the change in time: 55 feet / 5.25 seconds = 10.48 feet/second.
Therefore, the correct answer is: The quotient that describes the rate of change in the squirrel's height above the ground is 10.48 feet/second.