A rabbit is packing lunches for his children. He has 90 carrots and 72 leaves of lettuce. If he is giving each bunny the same number of carrots and the same number of leaves of lettuce, how many baby bunnies must he have? He will have no extra vegetables after he packs the lunches.(1 point)
Responses
6
6
3
3
9
9
18
To find the number of baby bunnies, we need to find the greatest common divisor of 90 and 72.
Prime factorize 90: 2 * 3^2 * 5 = 2^1 * 3^2 * 5^1
Prime factorize 72: 2^3 * 3^2
The common factors are 2^1 and 3^2.
The greatest common divisor is 2^1 * 3^2 = 6.
Therefore, the rabbit must have 6 baby bunnies.
To determine the number of baby bunnies the rabbit must have, we need to find the common denominator between the number of carrots and leaves of lettuce. This common denominator will represent the number of baby bunnies.
The factors of 90 are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, and 90.
The factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72.
The common factors between 90 and 72 are: 1, 2, 3, 6, 9, and 18.
Therefore, the rabbit must have 6 baby bunnies in order to give each bunny the same number of carrots and the same number of leaves of lettuce.