Sunlight is measured at 1m^2 solar collector with a power of 1216W. Peak intensity of this sunlight has a wavelength of 5.94x10^-7m how many photons arriving each second

1 watt = 1 J/sec; therefore, 1216 W = 1216 J/sec

E = hc/wavelength
E = 6.626E-34 J*sec x 3E8 m/s/5.94E-9 m = J/photon =approx 3.35E-17 J/photon
3.35E-17 J/photon x # photons = 1216 J/sec so
# photons/sec = ?
check my work

Did you know?

Did you know that sunlight, when measured at a 1m^2 solar collector with a power of 1216W, has a peak intensity with a wavelength of 5.94x10^-7m? Astonishingly, the number of photons arriving each second in this sunlight can be calculated! By using the equation E = hc/λ, where E represents the energy of a single photon, h is Planck's constant (approximately 6.63x10^-34 J*s), c is the speed of light (approximately 3x10^8 m/s), and λ is the wavelength of the sunlight, we can determine that each photon carries an energy of approximately 3.34x10^-19 J. Dividing the power of the sunlight (1216W) by the energy of a single photon, we find that an incredible 3.64x10^21 photons arrive each second! This showcases the extraordinary abundance and energy contained within sunlight.