The distance between Albert's house and David's house was 800 km. At 10 am, Albert left his house and drove towards David's house at 70 km/h. David left his house 1/4 h later and drove towards Albert's house at 75 km/h. What time would they meet if they drove at the same speed without stopping? Leave the answer in 24-hour clock and correct to the nearest minute.
since distance = speed * time,
starting at time t=0 when Albert left home,
70t + 75(t - 1/4) = 800
t = 5.6466
check:
5.6466 * 70 = 395.26
5.3966 * 75 = 404.74
total = 800 km
so they meet at 10:00 + 5:38:48 = 13:38:48