fay was assign to make a bookmark and the length of the rectangular bookmark required to her is 20 plus twice its width if the perimeter of the bookmark is 340cm
Is there a question in there somewhere?
2(w + 2w+20) = 340
2 (L + W) = 340 ... L + W = 170
L = 2 W + 20
substituting ... 2 W + 20 + W = 170
solve for W , then substitute back to find L
To solve this problem, we can use algebraic equations. Let's assume the width of the rectangular bookmark is "x" cm.
According to the given information, the length of the bookmark is 20 plus twice its width. Therefore, the length can be expressed as 20 + 2x.
The perimeter of a rectangle is calculated by adding twice the length and twice the width. In this case, the perimeter is given as 340 cm. So we can set up the equation:
2(length) + 2(width) = perimeter
Replacing the length and width expressions, we have:
2(20 + 2x) + 2x = 340
Now, let's solve this equation step by step:
2(20 + 2x) + 2x = 340
40 + 4x + 2x = 340 (Distributing 2 to both terms within the parentheses)
6x + 40 = 340 (Combining like terms)
6x = 300 (Subtracting 40 from both sides)
x = 50 (Dividing both sides by 6)
Therefore, the width of the rectangular bookmark is 50 cm. And if we substitute this value back into the length equation, we can find the length:
Length = 20 + 2x = 20 + 2(50) = 20 + 100 = 120 cm
So, the length of the rectangular bookmark is 120 cm.