A bowling ball travelling with a constant velocity hits the pins at the end of a bowling lane 19.80m long. The bowler hears the sound of the ball hitting the pins 4.8s after the ball is released from his hands. What is the velocity of the ball? speed of sound is 343 m/s
time elapsed=timeforballTraveling+timeforSound
where time for ballTraveling= 19.8/Vs
and Time for sound=19.8/343
solve for Vs
d = Vs*T = 19.8
343T = 19.8
T = 0.058 s.
d = Vb*T
19.8 = Vb(4.8-0.058)
Vb =
To find the velocity of the ball, we can use the equation:
velocity = distance / time
In this case, the distance is the length of the bowling lane, which is given as 19.80m. The time is the difference between when the ball is released and when the bowler hears the sound of the ball hitting the pins, which is given as 4.8s.
So, substituting the values into the equation:
velocity = 19.80m / 4.8s
Simplifying the calculation gives:
velocity ≈ 4.125m/s
Therefore, the velocity of the bowling ball is approximately 4.125 m/s.