A bowling ball is traveling at 7.6 meters per second when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
KE=12mv2
(1 point)
Responses
173.28 J
173.28 J
346.65 J
346.65 J
22.8 J
22.8 J
693.12 J
To calculate the kinetic energy (KE) of the bowling ball, we can use the formula KE = 1/2 * m * v^2, where m is the mass of the ball and v is its velocity.
Here, the mass of the bowling ball is given as 6 kilograms (m = 6 kg) and the velocity is given as 7.6 meters per second (v = 7.6 m/s).
Plugging these values into the formula, we get:
KE = 1/2 * 6 kg * (7.6 m/s)^2
Simplifying this equation:
KE = 1/2 * 6 kg * 57.76 m^2/s^2
KE = 3 kg * 57.76 m^2/s^2
KE = 173.28 Joules
Therefore, the bowling ball has 173.28 Joules of kinetic energy when it hits the pin. So, the correct answer is:
173.28 J