how many liters of ammonia gas will be produced when 44.8L of nitrogen reacts with hydrogen ?
Depends on the reaction. Are you thinking of the only therodynamically stable reaction...
N2 + 3H2>>>2NH3
The law of volues states it will take 3 times as much hydrogen than Nitrogen.
44 .8 l
To determine the amount of ammonia gas that will be produced, we need to first consider the balanced chemical equation for the reaction:
N₂ + 3H₂ → 2NH₃
From the equation, we can see that one mole of nitrogen reacts with three moles of hydrogen to produce two moles of ammonia.
To find the number of moles of nitrogen, we need to convert the volume of nitrogen gas from liters to moles using the ideal gas law. The ideal gas law states:
PV = nRT
Where:
P = pressure of the gas
V = volume of the gas
n = number of moles
R = ideal gas constant
T = temperature in Kelvin
Since the pressure, temperature, and gas constant are not given, we can assume they are constant for this calculation. Therefore, we can use the volume of nitrogen gas directly.
Now, we can calculate the number of moles of nitrogen:
n(N₂) = V(N₂) / 22.4
Where:
V(N₂) = volume of nitrogen gas (44.8 L)
22.4 L is the molar volume of any gas at standard temperature and pressure (STP).
n(N₂) = 44.8 L / 22.4 L/mol = 2 moles of nitrogen
According to the balanced equation, 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Therefore, for 2 moles of nitrogen, we would need 6 moles of hydrogen.
Now, to find the volume of ammonia gas produced in liters, we use the molar volume of gas at STP:
V(NH₃) = n(NH₃) x 22.4
Where:
n(NH₃) = number of moles of ammonia
22.4 L is the molar volume of any gas at STP.
Since 1 mole of nitrogen produces 2 moles of ammonia, and we have 2 moles of nitrogen, we will have 4 moles of ammonia:
n(NH₃) = 4 moles
V(NH₃) = 4 moles x 22.4 L/mol = 89.6 L
Therefore, when 44.8 L of nitrogen reacts with hydrogen, it will produce 89.6 L of ammonia gas.