Question 18 (2 points)
In the equation below, Nitrogen gas (N2) and Hydrogen gas (H2) react to produce Ammonia (NH3).
N2(g)+3H2(g)--->2NH3(g)
If 6.30 grams of Hydrogen reacts completely with nitrogen, how many grams of ammonia will be produced?
The molar mass of Hydrogen gas (H2)is 2.0 grams/mol.
The molar mass of Ammonia (NH3) is 17.0 grams/mol.
If you are unsure how to convert from grams to grams, please see the example problem linked HERE.
a
35.7 grams of NH3
b
38.5 grams of NH3
c
143 grams of NH3
d
80.3 grams of NH3
First, we need to determine the amount of NH3 produced when 6.30 grams of H2 reacts completely.
1. Calculate the number of moles of H2:
6.30 grams H2 * (1 mol / 2.0 grams) = 3.15 mol H2
2. Use the mole ratio from the balanced chemical equation to determine the moles of NH3 produced:
3.15 mol H2 * (2 mol NH3 / 3 mol H2) = 2.10 mol NH3
3. Calculate the mass of NH3 produced:
2.10 mol NH3 * 17.0 grams/mol = 35.7 grams of NH3
Therefore, the answer is a) 35.7 grams of NH3.