Ammonia, NH3, is widely used as a fertilizer and in many household cleaners. How many moles of ammonia are produced when 6 mol of hydrogen gas react with an excess of nitrogen gas?
N2 + 3H2 ==> 2NH3
The equation tell you that you get 2 mols NH3 for every 3 mols H2 so if you have 6 mols H2 gas (instead of 3) wouldn't you think you would get 4 mols NH3? Or in good math terms.
6 mols H2 gas x (2 mols NH3/3 mol H2) = 4 mols NH3.
Well, isn't this an explosive combination of gases? It's like a chemistry version of a buddy cop movie! Okay, here's the deal: when hydrogen (H2) reacts with nitrogen (N2) to form ammonia (NH3), the equation is:
3H2 + N2 → 2NH3
So, for every two moles of ammonia produced, you need three moles of hydrogen. Since you have 6 moles of hydrogen, you can produce twice as much ammonia. That means you'll have 4 moles of ammonia! Voila! Just remember, this chemical reaction is more than just a "nitrogen" success.
To determine the number of moles of ammonia produced when 6 moles of hydrogen gas react with an excess of nitrogen gas, we need to refer to the balanced chemical equation for this reaction.
The balanced equation for the formation of ammonia (NH3) from nitrogen gas (N2) and hydrogen gas (H2) is:
N2 + 3H2 → 2NH3
According to the stoichiometry of the equation, for every 3 moles of hydrogen gas, we can produce 2 moles of ammonia.
Therefore, if we start with 6 moles of hydrogen gas and assume an excess of nitrogen gas, we can calculate the moles of ammonia produced as follows:
(6 mol H2) x (2 mol NH3 / 3 mol H2) = 4 mol NH3
Hence, 4 moles of ammonia are produced when 6 moles of hydrogen gas react with an excess of nitrogen gas.
To determine the moles of ammonia produced when hydrogen gas reacts with nitrogen gas, we first need to balance the chemical equation for the reaction. The balanced equation for the reaction is as follows:
N2 + 3H2 → 2NH3
This means that one molecule of nitrogen gas (N2) reacts with three molecules of hydrogen gas (H2) to produce two molecules of ammonia (NH3).
Since the ratio of moles in the balanced equation is 1:3:2 (1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3), we can use this ratio to determine the moles of ammonia produced.
In this case, we have 6 moles of hydrogen gas (H2). According to the balanced equation, 3 moles of H2 are required to produce 2 moles of ammonia.
Thus, to calculate the moles of ammonia, we can use the following proportion:
3 mol H2 / 2 mol NH3 = 6 mol H2 / x mol NH3
Cross multiplying, we get:
3 mol H2 * x mol NH3 = 2 mol NH3 * 6 mol H2
Simplifying, we find:
3x = 12
Dividing both sides of the equation by 3, we get:
x = 4
Therefore, when 6 moles of hydrogen gas react with an excess of nitrogen gas, 4 moles of ammonia are produced.