A drop of oil volume 10^-10m^3 spreads out on water to make a circular firm of radius 10^-1.what is the thickness of the firm.
Volume = pi^r^2*h
You know the volume and the radius from the problem Substitute and solve for h. (the thickness)
yes
Give the explanation
Of the first one
To find the thickness of the oil film, we can use the formula for the volume of a cylinder.
The volume of the oil film can be treated as a cylinder, where the oil spreads out in a circular form on water. Given that the volume of the oil droplet is 10^-10 m^3, we can use the formula:
Volume of a cylinder = π * radius^2 * height
Here, the radius of the circular oil film is given as 10^-1 m.
We need to find the height or thickness of the film, which is denoted by "h" in the formula.
Since the oil film spreads out on the water, we can assume that the radius of the circular film remains the same after spreading.
So, the volume of the oil droplet is equal to the volume of the cylinder formed by the film:
10^-10 m^3 = π * (10^-1 m)^2 * h
Simplifying the equation, we get:
h = (10^-10 m^3) / (π * (10^-1 m)^2)
h = (10^-10 m^3) / (π * 10^-2 m^2)
h = (10^-10 m^3) / (π * 10^-2 m^2)
h = 10^-8 / π
h ≈ 3.18 × 10^-9 meters (or approximately 0.318 nanometers)
Therefore, the thickness of the oil film is approximately 0.318 nanometers.