For the equation
y + 2 = -3/2(x-6)
Identify the point found in the equation.
Help?? what point are they talking about? =/
Excellent question. You could rearrange the equation to point slope format, and state the y intercept, but that just begs the question: What point are they talking about.
Was there another equation? What we're looking at is the equation of a line, not a point. You'd need a second line to define a point, which would be the intersection of the two (assuming there was an intersection, of course).
In the given equation, "y + 2 = -3/2(x-6)," the point being referred to is the solution to the equation. It is the coordinate point (x, y) that satisfies the equation when both x and y are substituted into the equation. To find this point, you need to solve the equation for either x or y.
Let's solve it for y:
Start with the equation:
y + 2 = -3/2(x-6)
First, distribute the -3/2 to (x-6):
y + 2 = -3/2x + 9
Next, isolate y by subtracting 2 from both sides:
y = -3/2x + 9 - 2
y = -3/2x + 7
Now, you have the equation in slope-intercept form (y = mx + b), where the coefficient of x (-3/2) represents the slope, and 7 represents the y-intercept.
So, the point found in this equation is the coordinate point (x, y) where y = -3/2x + 7.