# Physics URGENT HELP

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An athlete is training and is required to perform shuttle runs. From the starting position they sprint out to 10m (this takes 2 seconds).

• Physics URGENT HELP -

10 = (1/2) a t^2

20 = a (4)

a = 5 m/s^2

• Physics URGENT HELP -

Thankyou, but I need to establish where within the run max acceleration occurs (what metre mark?)

• Physics URGENT HELP -

I suspect if they turn around at the end, the max acceleration occurs there.

• Physics URGENT HELP -

I think I know what you were looking for. Starting off where Damon left off,

Max acceleration occurs when the velocity=acceleration.

Vi=0m/s^2
Vf=5m/s and
a=5m/s^2
d=?

Solve for d.

(5m/s)^2=0+2(5m/s^2)d

25=10d
25/10=d

d=2.5m

The runner establishes max acceleration at the 2.5m mark in the race.

Hope I helped in time.

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