the french club is sponsering a bake sale. they spent $77 in supplies. if their goal is to raise at least $140 how many pastries must they sell at $3.50 each in order to meet the goal. write and solve an inequality.
a. 140p-77≥ 3.50;p≥ 0.5
b. 140p+77≥3.50; p≥62
c. 3.50p+77≥140; p≥17
d. 3.50p-77≥140; p≥62
c
To solve this problem, let's set up an inequality:
Let p be the number of pastries they must sell.
The cost of supplies is $77.
The price of each pastry is $3.50.
The total amount they need to raise is at least $140.
We can express the equation as:
3.50p + 77 ≥ 140
To solve for p, we need to isolate it on one side of the inequality. We can do this by subtracting 77 from both sides:
3.50p ≥ 140 - 77
3.50p ≥ 63
Now, to solve for p, we need to divide both sides by 3.50:
p ≥ 63 ÷ 3.50
p ≥ 18
Therefore, the correct answer is option c. The French club needs to sell at least 18 pastries in order to meet their goal of raising at least $140.