Derek threw the football 36 2/3 yards during Tuesday's game. The next play he threw the football 2 5/6 yards less. How far was his second pass thrown?
33?
No.
36 2/3 = 35 5/3 = 35 10/6
Subtract 2 5/6 from 35 10/6
How do you figure out 36 2/3=35 5/3 and how does 35 5/3= 35 10/6?
I found out how 36 2/3=35 5/3 but how does it equal 35 10/6
I borrowed 3/3 from 36 to get 35.
35 5/3
We need to find a common denominator so I multiplied the numerator and denominator by 2 to get 35 10/6
The answer is 33 5/6?
Right. :-)
To find out how far Derek's second pass was thrown, we need to subtract 2 5/6 yards from his initial throw of 36 2/3 yards.
To subtract mixed numbers, we first need to convert them into improper fractions.
36 2/3 can be converted into an improper fraction by multiplying the whole number (36) by the denominator (3) and adding the numerator (2). This gives us (36 * 3 + 2) / 3 = 110/3.
2 5/6 can be converted into an improper fraction by multiplying the whole number (2) by the denominator (6) and adding the numerator (5). This gives us (2 * 6 + 5) / 6 = 17/6.
Now, we can subtract the fractions:
110/3 - 17/6
To subtract fractions, we need a common denominator. The least common multiple (LCM) of 3 and 6 is 6.
Converting both fractions to have a denominator of 6:
110/3 = (110/3) * (2/2) = 220/6
17/6 = 17/6
Now we can subtract the fractions:
220/6 - 17/6 = (220 - 17) / 6 = 203/6
The second pass was thrown 203/6 yards.
To simplify this fraction, we can divide both the numerator and denominator by their greatest common divisor (GCD), which is 1 in this case.
So, 203/6 is already in simplest form.
Therefore, Derek's second pass was thrown 203/6 yards.