An electric kettle operates at 110V. What is the resistance of the kettle if the power is 1.5kW?
8.1 Ω
1.4 Ω
81 Ω
14 Ω
Both A and B seem reasonable, and I'm leaning more towards B. Help..?
it's A
To find the resistance of the electric kettle, we can use Ohm's Law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I).
In this case, we are given the power (P) of the kettle, which is 1.5 kW, and the voltage (V) of 110V. We can calculate the current (I) using the formula P = IV.
1.5 kW = 110V * I
I = 1.5 kW / 110V
I = 0.0136 A
Now that we have the current, we can calculate the resistance using Ohm's Law:
R = V / I
R = 110V / 0.0136 A
R ≈ 8.088 Ω
So, the resistance of the kettle is approximately 8.088 Ω. Since none of the given options match exactly, the closest answer is 8.1 Ω (option A).