An electric kettle is rated 2kilowatt,240 volt and when filled with cold water takes 5mins to boil. Calculate the resistance of the element when the kettle is in used
r = v^2 / w
To calculate the resistance of the element in the kettle, we can use Ohm's Law, which states that resistance (R) is equal to voltage (V) squared divided by power (P).
Given:
Power (P) = 2 kilowatts = 2000 watts
Voltage (V) = 240 volts
First, convert the power from kilowatts to watts:
P = 2 kilowatts = 2000 watts
Now, we can calculate the resistance:
R = V^2 / P
R = (240^2) / 2000
R = 57600 / 2000
R = 28.8 ohms
Therefore, the resistance of the element in the kettle when it is in use is 28.8 ohms.
To calculate the resistance of the element in the electric kettle when it is in use, we can use Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I) flowing through the element.
1. We know the power rating of the kettle is 2 kilowatts (kW). Power (P) is given by the formula P = V * I, where V is the voltage and I is the current.
2. We can convert the power rating to watts by multiplying it by 1000. So, the power rating is 2,000 watts (2 kW * 1000).
3. The voltage of the kettle is given as 240 volts (V).
4. We need to find the current (I) flowing through the element. To do this, we can rearrange the power formula: P = V * I.
Solving for I, we get I = P / V.
Plugging in the values, we have I = 2000 watts / 240 volts.
5. Calculate the current: I = 8.33 amperes (A) (2000 watts / 240 volts).
6. Now we can calculate the resistance (R) of the element in the kettle using Ohm's Law: R = V / I.
Plugging in the values, we get R = 240 volts / 8.33 amperes.
7. Calculate the resistance: R = 28.83 ohms (240 volts / 8.33 amperes).
Therefore, the resistance of the element in the electric kettle when it is in use is approximately 28.83 ohms.