Ms. Avari is lifting 65 kg weights in kettle bell class. She needs to swing the kettle bell over her head, a total of 2 meters off the ground. What potential energy do the weight when Ms. Avari is holding it over her head?
a
1275.3 J
b
520 J
c
130 J
d
260 J
e
2,550.6 J
f
637.65 J
The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.
In this case, the mass of the weight is 65 kg, the acceleration due to gravity is 9.8 m/s^2, and the height that Ms. Avari lifts the weight is 2 meters.
PE = (65 kg)(9.8 m/s^2)(2 m) = 1,274 J
Therefore, the answer is (a) 1275.3 J (rounded to the nearest tenth).
To determine the potential energy of the weight when Ms. Avari is holding it over her head, you can use the formula:
Potential Energy (PE) = mass (m) * gravitational acceleration (g) * height (h)
Given that the mass of the weight is 65 kg and the height is 2 meters, and assuming the gravitational acceleration is approximately 9.8 m/s^2, you can plug in the values and calculate the potential energy:
PE = 65 kg * 9.8 m/s^2 * 2 m
PE = 1274 J (approximately)
Therefore, the potential energy of the weight when Ms. Avari is holding it over her head is approximately 1275.3 J.
So, the correct option is a) 1275.3 J.
To calculate the potential energy of the weight when Ms. Avari is holding it over her head, we can use the formula for potential energy:
Potential Energy (PE) = mass (m) × acceleration due to gravity (g) × height (h)
Given:
Mass (m) = 65 kg
Height (h) = 2 meters
Acceleration due to gravity (g) = 9.8 m/s²
Substituting the given values into the formula:
PE = 65 kg × 9.8 m/s² × 2 meters
PE = 1274 J (rounded to the nearest whole number)
Therefore, the potential energy of the weight when Ms. Avari is holding it over her head is approximately 1274 J. The closest option from the given answer choices is 1275.3 J (option a).