What is the resistance of the element of a 1500 W kettle if it draws 12.5 A?
12.5 * r = 1500 / 12.5
I^2 * R = 1500
12.5^2 * R = 1500.
R =
To find the resistance of the element in the kettle, you can use Ohm's Law, which states that resistance (R) is equal to the voltage (V) divided by the current (I).
The power (P) of the kettle is given as 1500 W, and the current (I) is given as 12.5 A.
First, let's calculate the voltage (V) using the power formula. The power (P) is equal to the voltage (V) multiplied by the current (I):
P = V * I
1500 W = V * 12.5 A
Now we can solve for V:
V = 1500 W / 12.5 A
V = 120 V
Now that we have the voltage (V) and current (I), we can calculate the resistance (R) using Ohm's Law:
R = V / I
R = 120 V / 12.5 A
R = 9.6 Ω
Therefore, the resistance of the element in the kettle is 9.6 Ω.
To find the resistance of the heating element in the kettle, you can use Ohm's Law, which states that resistance (R) is equal to the voltage (V) divided by the current (I), or R = V/I.
In this case, we are given the power (P) consumed by the kettle, which is 1500 W, and the current (I) drawn by the kettle, which is 12.5 A.
First, we need to calculate the voltage (V) using the power formula: P = V * I. Rearranging the formula to solve for V gives us V = P/I.
Let's substitute the given values into the formula to find V: V = 1500 W / 12.5 A = 120 V.
Now that we have the voltage (V) and the current (I), we can calculate the resistance (R) using Ohm's Law: R = V/I.
Substituting the values, we get R = 120 V / 12.5 A = 9.6 ohms.
Therefore, the resistance of the heating element in the kettle is 9.6 ohms.