Joan has one more than 3 times as many cassette tapes as Paul has. Together
they have 25 tapes. How many tapes does Paul have?
ANS: 6 tapes
The answer is 6 tapes. Does anyone know how to do this problem?
To solve this problem, we can set up a system of equations. Let's use P to represent the number of cassette tapes that Paul has and J to represent the number of cassette tapes that Joan has.
According to the problem statement, Joan has one more than 3 times as many cassette tapes as Paul has. So, we can write the equation:
J = 3P + 1
We also know that together they have 25 tapes. So, we can write the equation:
J + P = 25
Now, we can solve this system of equations to find the number of tapes that Paul has.
Substituting the value of J from the first equation into the second equation, we get:
(3P + 1) + P = 25
Simplifying this equation, we get:
4P + 1 = 25
Subtracting 1 from both sides, we get:
4P = 24
Dividing both sides by 4, we get:
P = 6
So, Paul has 6 tapes.
J-1=3P
J+P=25