. Given the following stocks 4M NaCl, 3M NaOH, 5M HCl

(a) Prepare 200ml of a solution containing 0.5M NaCl and 0.1M
(b) Prepare 300ml of a solution containing 0.5M NaCl
(c) Prepare 200ml of a solution containing 0.5M NaCl and 0.1M HCl

Your questin is messed up on a.

c. you want one part stock NaCl, 7 parts other. But you also want (5/.1) a dilution of 5O for the stock HCl, so one part of HCL is 200/50=4ml, so add 4ml of stock HCl, now the remainder water:
Remainder=200-6-50=144ml water.
You now have .5MNaCl with .1MHCl, a very odd combination.

Answer

To prepare the desired solutions, we can use the Dilution Formula:

C1V1 = C2V2

Where:
C1 = concentration of the initial solution
V1 = volume of the initial solution
C2 = concentration of the final solution
V2 = volume of the final solution

(a) Prepare 200ml of a solution containing 0.5M NaCl and 0.1M NaOH:
1. Calculate the volume of the 4M NaCl solution needed:
C1V1 = C2V2
(4M)(V1) = (0.5M)(200ml)
V1 = (0.5M)(200ml) / (4M)
V1 = 25ml

2. Calculate the volume of the 3M NaOH solution needed:
C1V1 = C2V2
(3M)(V1) = (0.1M)(200ml)
V1 = (0.1M)(200ml) / (3M)
V1 = 6.67ml

3. Measure 25ml of the 4M NaCl solution and 6.67ml of the 3M NaOH solution using a pipette or burette.

4. Transfer both solutions into a 200ml volumetric flask.

5. Fill the volumetric flask to the mark with distilled water while swirling gently to mix the solutions.

(b) Prepare 300ml of a solution containing 0.5M NaCl:
1. Calculate the volume of the 4M NaCl solution needed:
C1V1 = C2V2
(4M)(V1) = (0.5M)(300ml)
V1 = (0.5M)(300ml) / (4M)
V1 = 37.5ml

2. Measure 37.5ml of the 4M NaCl solution using a pipette or burette.

3. Transfer the solution into a 300ml volumetric flask.

4. Fill the volumetric flask to the mark with distilled water while swirling gently to mix the solution.

(c) Prepare 200ml of a solution containing 0.5M NaCl and 0.1M HCl:

1. Calculate the volume of the 4M NaCl solution needed:
C1V1 = C2V2
(4M)(V1) = (0.5M)(200ml)
V1 = (0.5M)(200ml) / (4M)
V1 = 25ml

2. Calculate the volume of the 5M HCl solution needed:
C1V1 = C2V2
(5M)(V1) = (0.1M)(200ml)
V1 = (0.1M)(200ml) / (5M)
V1 = 4ml

3. Measure 25ml of the 4M NaCl solution and 4ml of the 5M HCl solution using a pipette or burette.

4. Transfer both solutions into a 200ml volumetric flask.

5. Fill the volumetric flask to the mark with distilled water while swirling gently to mix the solutions.