HCl is a strong acid and ionizes 100%.
NaOH is a strong base and ionizes 100%.
We have no way of knowing the pH of HCl + H2O because the problem doesn't state the amount of HCl added or the concentration of HCl.
For the NaOH + HCl ==> NaCl + HOH.
NaCl in water is a neutral solution.
What are the pH's of the final solutions that would be formed from these equations:
HCl+H20--->
NaOH+HCl--->
please and thanks
okay, thanks, well, i guess i'll just pick a high number then
To determine the pH of the final solutions, we need to consider the properties of the acids and bases involved.
1. HCl + H2O:
Since the problem does not provide the amount or concentration of HCl added, we cannot directly calculate the pH. However, given that HCl is a strong acid and ionizes 100% in water, it will dissociate into H+ and Cl- ions. The resulting solution will be highly acidic.
2. NaOH + HCl:
When NaOH, a strong base, reacts with HCl, a strong acid, it forms NaCl (sodium chloride) and H2O (water). NaCl is a neutral compound. The resulting solution will be neutral with a pH of 7.
Therefore, picking a high number for the pH of the first equation is not accurate since the information needed to calculate it is missing. The pH of the second equation, NaOH + HCl, will be 7, indicating neutrality.