Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three vertical rectangles placed vertically one on top of the other. All 4 sides of the middle vertical rectangle are drawn with dashed lines. The width of the rectangles is 10 feet. The length of the middle rectangle is 24 feet. Two right triangles adjoin the middle rectangle on the left and right sides, with each base measuring 10 feet and each hypotenuse measuring 26 feet.
Using the net of the triangular prism, what is its surface area?
(1 point)
Responses
840 ft.2
840 ft. squared
1,200 ft.2
1,200 mi. squared
240 ft.2
240 ft. squared
720 ft.2
720 ft. squared
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To find the surface area of the triangular prism, we need to find the area of each individual shape on the net and then add them together.
1. The area of the middle rectangle is 10 feet (width) x 24 feet (length) = 240 ft^2.
2. The area of the two right triangles is 2 x (1/2 x 10 feet x 24 feet) = 240 ft^2 (for both triangles).
3. The area of each of the three vertical rectangles is 10 feet x 24 feet = 240 ft^2.
Adding these together, the total surface area of the triangular prism is 240 ft^2 + 240 ft^2 + 240 ft^2 = 720 ft^2.
Therefore, the correct answer is 720 ft^2.