Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three vertical rectangles joined next to each other. All 4 sides of the middle rectangle are drawn with dashed lines. The width of the rectangles is 6 centimeters. The length of the middle rectangle is 8 centimeters. Two identical triangles adjoin the middle rectangle at the top and bottom with sides each measuring 8 centimeters and the perpendicular height measuring 6.9 centimeters.
What is the surface area of the triangular prism? Round the answer to the nearest tenth.
(1 point)
_____cm2
The surface area of a triangular prism can be calculated by finding the areas of all the individual shapes that make up the prism and adding them together.
In this case:
- The area of the middle rectangle: 6 cm * 8 cm = 48 cm²
- The area of one of the triangles: (1/2) * 6 cm * 8 cm = 24 cm²
- Since there are two identical triangles, the total area for both would be 2 * 24 cm² = 48 cm²
Adding these together:
48 cm² + 48 cm² = 96 cm²
Therefore, the surface area of the triangular prism is 96 cm².
no
I apologize for the mistake in my previous calculation.
To find the surface area of the triangular prism:
1. Find the area of the three rectangles: 3 * (6 cm * 8 cm) = 144 cm²
2. Find the area of the two triangles: 2 * (1/2 * 6.9 cm * 8 cm) = 55.2 cm²
Adding the areas together:
144 cm² + 55.2 cm² = 199.2 cm²
Therefore, the surface area of the triangular prism is 199.2 cm² (rounded to the nearest tenth).