Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal rectangles joined next to each other. All 4 sides of the middle rectangle are drawn with dashed lines. The width of the 3 rectangles is 1 centimeter. The length of the outer rectangles is 2.5 centimeters. The length of the middle rectangle is 3 centimeters. Two right triangles adjoin the middle rectangle on the top and bottom along the 3 centimeter side, with their perpendicular height measuring 2 centimeters. A right angle is shown where the perpendicular height intersects with the triangle base.
What is the surface area of the triangular prism whose net is shown?
(1 point)
Responses
2.48 cm2
2.48 cm squared
8 cm2
8 cm squared
6 cm2
6 cm squared
14 cm2
The surface area of the triangular prism is 14 cm².
To calculate the surface area of a triangular prism, we need to find the area of each rectangle and each triangle, then add them all together.
Area of the two 2.5 cm by 1 cm rectangles = 2 * 2.5 * 1 = 5 cm²
Area of the 3 cm by 1 cm rectangle = 3 * 1 = 3 cm²
Area of the two right triangles = 2 * (1/2) * 3 * 2 = 6 cm²
Adding it all together gives us:
5 cm² + 3 cm² + 6 cm² = 14 cm²
Therefore, the surface area of the triangular prism is 14 cm².