Solve the system of two equations, using elimination with multiplication
4X minus 6Y equals -48
Negative 2X plus 4Y equals 30
First, we need to eliminate one of the variables. Let's choose to eliminate X.
Multiply the first equation by 2 and the second equation by 4 to both get a coefficient of -8X:
8X - 12Y = -96
-8X + 16Y = 120
Now, add the two equations together:
8X - 12Y + (-8X + 16Y) = -96 + 120
4Y = 24
Y = 6
Now substitute Y = 6 into the first equation:
4X - 6(6) = -48
4X - 36 = -48
4X = -12
X = -3
Therefore, the solution to the system of equations is X = -3 and Y = 6.