Solve the system of equations using elimination: minus, x, minus, 8, y, equals, 49−x−8y=49 and minus, x, minus, 2, y, equals, 7−x−2y=7.
To solve the system of equations using the elimination method, we need to eliminate one of the variables by multiplying one or both equations by suitable constants so that we can add or subtract the two equations to eliminate that variable.
To eliminate the "x" variable, we can multiply the second equation by -1:
-1(-x - 2y) = -1(7)
x + 2y = -7
Now we have the equations:
-x - 8y = 49
x + 2y = -7
We can add these two equations together to eliminate the "x" variable:
(-x - 8y) + (x + 2y) = 49 + (-7)
-6y = 42
y = -7
Now, substitute the value of "y" into one of the original equations:
-x - 8(-7) = 49
-x + 56 = 49
-x = -7
x = 7
Therefore, the solution to the system of equations is x = 7 and y = -7.