Solve the system of two equations using elimination with multiplication. 4x- 6y = -48 and -2x + 4y = 30. A. (-3, 6) b. (-21, -6) c. (3, 9) d. (-33, -9)
To solve the system of equations using elimination with multiplication, we need to eliminate one variable by multiplying one or both equations by a suitable number, so that when we add or subtract the two equations, one of the variables cancels out.
First, let's multiply the second equation by 2 to make the x coefficients equal:
-2x + 4y = 30
2(-2x + 4y) = 2(30)
-4x + 8y = 60
Now, we can add the two equations together to eliminate the x variable:
4x - 6y + (-4x + 8y) = -48 + 60
-6y + 8y = 12
2y = 12
y = 6
Now substitute the value of y into one of the original equations to solve for x:
4x - 6(6) = -48
4x - 36 = -48
4x = -48 + 36
4x = -12
x = -12/4
x = -3
Therefore, the solution to the system of equations is (-3, 6).
The correct answer is A. (-3, 6).