Show your work as to how to identify the zeros in this quadratic equation y=-(x-2)^2 +4, and to show your answer in SERIES NOTATION { }
To find the zeros of a quadratic equation, we need to set the equation equal to zero and solve for x.
Given the quadratic equation:
y = -(x-2)^2 + 4
Setting y to zero:
0 = -(x-2)^2 + 4
Now, we can solve for x by rearranging the equation:
(x-2)^2 = 4
x - 2 = ±√4
x - 2 = ±2
x = 2 ± 2
x = 4 or x = 0
Therefore, the zeros of the quadratic equation y = -(x-2)^2 + 4 are x = 4 and x = 0.
Writing the answer in series notation, the zeros can be shown as:
{4, 0}