Is (10,–3) a solution to this system of inequalities?
19x–17y≤–2
20x+16y>16
To determine if (10, -3) is a solution to the system of inequalities, we can substitute the values of x and y into the inequalities and see if they hold true.
1. Substitute x = 10 and y = -3 into the first inequality:
19(10) - 17(-3) ≤ -2
190 + 51 ≤ -2
241 ≤ -2
This inequality is false.
2. Substitute x = 10 and y = -3 into the second inequality:
20(10) + 16(-3) > 16
200 - 48 > 16
152 > 16
This inequality is true.
Since (10, -3) satisfies the second inequality but not the first, it is not a solution to the system of inequalities.