3x + 19y = 2 19x + 3y = 130 What is the solution for the system of equations above?
To solve this system of equations, we can use the method of substitution or elimination.
Let's use the method of substitution:
From the first equation, we can solve for x:
3x = 2 - 19y
x = (2 - 19y)/3
Now, substitute the value of x in the second equation:
19(2 - 19y)/3 + 3y = 130
Simplify the equation:
38 - 361y/3 + 3y = 130
Multiply through by 3 to get rid of the fraction:
114 - 361y + 9y = 390
Combine like terms:
-352y = 276
Divide by -352 to solve for y:
y = -276/-352
y = 69/88
Substitute this value back into the first equation to solve for x:
3x + 19(69/88) = 2
3x + 1311/88 = 2
3x = 1768/88 - 1311/88
3x = 457/88
x = 457/264
Therefore, the solution to the system of equations is x = 457/264 and y = 69/88.