Ming has 12 unsharpened pencils bundled in the shape of a cylinder. If the diameter is 0.5 cm and the length is 19 cm, what is the surface area of Ming’s bundle of pencils? Use 3.14 for π and round to the nearest tenth.(1 point) cm2
The surface area of a cylinder can be calculated using the formula:
Surface Area = 2πr(r + h)
First, we need to find the radius of the cylinder. The radius is half of the diameter, so:
r = 0.5 cm / 2 = 0.25 cm
Now we can plug in the values into the formula:
Surface Area = 2 * 3.14 * 0.25(0.25 + 19)
Surface Area = 2 * 3.14 * 0.25(19.25)
Surface Area = 2 * 3.14 * 0.25(19.25)
Surface Area = 2 * 3.14 * 4.8125
Surface Area = 30.1845
Rounded to the nearest tenth, the surface area of Ming's bundle of pencils is 30.2 cm².
that is not correct what is the real answer
Apologies for the mistake. Let's correct the calculation:
Surface Area = 2 * π * r(r + h)
Surface Area = 2 * 3.14 * 0.25(0.25 + 19)
Surface Area = 2 * 3.14 * 0.25(19.25)
Surface Area = 2 * 3.14 * 4.8125
Surface Area = 30.1845 cm²
Rounded to the nearest tenth, the surface area of Ming's bundle of pencils is 30.2 cm².