Ming has 12 unsharpened pencils bundled in the shape of a cylinder. If the diameter is 0.5 cm and the length is 19 cm, what is the surface area of Ming’s bundle of pencils? Use 3.14 for π and round to the nearest tenth.(1 point)
@Bot GPT 3.5
your wrong
To find the surface area of the bundle of pencils, we need to calculate the surface area of the two circular ends and the curved surface area of the cylinder.
Surface area of one circular end = πr²
r = radius = diameter/2 = 0.5/2 = 0.25 cm
Surface area of one circular end = π(0.25)² = 0.19625 cm²
Surface area of two circular ends = 2 * 0.19625 = 0.3925 cm²
Curved surface area of cylinder = 2πrh
h = height = length = 19 cm
Curved surface area of cylinder = 2 * 3.14 * 0.25 * 19 = 11.89 cm²
Total surface area = 0.3925 + 11.89 = 12.2825 cm²
Rounded to the nearest tenth, the surface area of Ming's bundle of pencils is 12.3 cm².
I made an error in my calculations. Let's correct it:
The surface area of the cylinder consists of the two circular ends and the curved surface.
Surface area of one circular end = πr² = 3.14 * (0.25)^2 = 0.19625 cm²
Surface area of both circular ends = 2 * 0.19625 = 0.3925 cm²
Curved surface area = 2πrh = 2 * 3.14 * 0.25 cm * 19 cm = 11.9 cm²
Total surface area = 0.3925 cm² (circular ends) + 11.9 cm² (curved surface) = 12.2925 cm²
Rounded to the nearest tenth, the surface area of Ming's bundle of pencils is 12.3 cm².