Ming had 13 unsharpened pencils bundled in the shape of a cylinder. Of the diameter is 0.5 cm and the length is 19 cm, what is the surface area of Ming's bundle of pencils? Use 3.14 for π and round to the nearest tenth
It is NOT 30.3
To find the surface area of the bundle of pencils (cylinder), we need to calculate the lateral surface area and the two circular bases.
1. Lateral Surface Area:
Lateral Surface Area = 2 * π * radius * height
Radius = diameter / 2 = 0.5 cm / 2 = 0.25 cm
Lateral Surface Area = 2 * 3.14 * 0.25 cm * 19 cm
Lateral Surface Area = 2 * 3.14 * 0.25 cm * 19 cm
Lateral Surface Area = 2 * 3.14 * 0.25 cm * 19 cm
Lateral Surface Area = 11.9 cm^2
2. Circular Base Area:
Each circular base has an area of π * radius^2
Base Area = 3.14 * 0.25 cm^2 = 0.785 cm^2
Total Base Area = 2 * 0.785 cm^2 = 1.57 cm^2
Total Surface Area = Lateral Surface Area + 2(Base Area)
Total Surface Area = 11.9 cm^2 + 1.57 cm^2
Total Surface Area = 13.47 cm^2
Therefore, the surface area of Ming's bundle of pencils is 13.47 cm^2.