Ming had 13 unsharpened pencils bundled in the shape of a cylinder. Of the diameter is 0.5 cm and the length is 19 cm, what is the surface area of Ming's bundle of pencils? Use 3.14 for π and round to the nearest tenth
It is not 30.3 nor is it 13.47
The surface area of a cylinder can be calculated using the formula:
Surface Area = 2πr(r + h)
Given that the diameter is 0.5 cm (radius = 0.25 cm) and the length is 19 cm, we can plug these values into the formula:
Surface Area = 2 * 3.14 * 0.25(0.25 + 19)
Surface Area = 2 * 3.14 * 0.25(19.25)
Surface Area = 2 * 3.14 * 4.8125
Surface Area = 30.3195 cm²
Rounded to the nearest tenth, the surface area of Ming's bundle of pencils is 30.3 cm².