Joseph has a rain barrel in the shape of a cylinder with a height of 48 inches and a diameter of 24inches what is the surface area of the rain barrel use 3.14 for and round to the nearest tenth
To find the surface area of the rain barrel, we need to calculate the area of the two circular ends and the lateral surface area.
1. Area of the circular ends:
The radius of the circular ends is half of the diameter, so the radius is 24/2 = 12 inches.
Area of one circular end = πr^2
Area of one circular end = 3.14 x 12^2
Area of one circular end = 3.14 x 144
Area of one circular end = 452.16 square inches
Since there are two circular ends, the total area of the circular ends is:
Total area of circular ends = 2 x 452.16
Total area of circular ends = 904.32 square inches
2. Lateral surface area:
The lateral surface area of a cylinder is given by the formula: 2πr x h, where r is the radius and h is the height.
Lateral surface area = 2 x 3.14 x 12 x 48
Lateral surface area = 3611.52 square inches
Total surface area of the rain barrel:
Total surface area = Total area of circular ends + Lateral surface area
Total surface area = 904.32 + 3611.52
Total surface area = 4515.84 square inches
Therefore, the surface area of the rain barrel is approximately 4515.8 square inches when rounded to the nearest tenth.