Joseph has a rain barrel in the shape of a cylinder with a height of 48 inches and a diameter of 24 inches. What is the surface area of the rain barrel? Use 3.14 for π and round to the nearest tenth.(1 point)in.2
The formula to calculate the surface area of a cylinder is 2πr² + 2πrh, where r is the radius of the base and h is the height of the cylinder.
First, we need to find the radius of the base. The diameter is 24 inches, so the radius is half of that, which is 12 inches.
Now we can plug the values into the formula:
Surface Area = 2(3.14)(12)² + 2(3.14)(12)(48)
Surface Area = 2(3.14)(144) + 2(3.14)(576)
Surface Area = 2(452.16) + 2(1808.64)
Surface Area = 904.32 + 3617.28
Surface Area = 4521.6
So, the surface area of the rain barrel is 4521.6 square inches.
Joseph has a rain barrel in the shape of a cylinder with a height of 48 inches and a diameter of 24 inches. What is the surface area of the rain barrel? Use 3.14 for π and round to the nearest tenth.(1 point)in.2
The formula to calculate the surface area of a cylinder is 2πrh + 2πr², where r is the radius and h is the height.
Given that the diameter is 24 inches, the radius, which is half of the diameter, is 12 inches. The height is 48 inches.
Plugging the values into the formula:
Surface Area = 2(3.14)(12)(48) + 2(3.14)(12)²
Surface Area = 2(3.14)(576) + 2(3.14)(144)
Surface Area = 2(1807.68) + 2(452.16)
Surface Area = 3615.36 + 904.32
Surface Area = 4520.68
Therefore, the surface area of the rain barrel is approximately 4520.7 square inches.
WRong
I apologize for the error in my previous calculation. Let's correct it.
Given:
Height (h) = 48 inches
Diameter = 24 inches
Radius (r) = 12 inches
To find the surface area of the cylinder, we use the formula:
Surface Area = 2πr(h + r)
Substitute the values:
Surface Area = 2 * 3.14 * 12(48 + 12)
Surface Area = 2 * 3.14 * 12 * 60
Surface Area = 2 * 3.14 * 720
Surface Area = 4523.2 square inches
Therefore, the surface area of the rain barrel is approximately 4523.2 square inches.
not right
I apologize for the error in my previous responses. Let's correct it now.
Given:
Height (h) = 48 inches
Diameter = 24 inches
Radius (r) = 12 inches
To find the surface area of the cylinder, we use the formula:
Surface Area = 2πr² + 2πrh
Substitute the values:
Surface Area = 2 * 3.14 * 12² + 2 * 3.14 * 12 * 48
Surface Area = 2 * 3.14 * 144 + 2 * 3.14 * 576
Surface Area = 904.32 + 3617.28
Surface Area = 4521.6 square inches
Therefore, the surface area of the rain barrel is approximately 4521.6 square inches.
no where near right
Ming has 12 unsharpened pencils bundled in the shape of a cylinder. If the diameter is 0.5 cm and the length is 19 cm, what is the surface area of Ming’s bundle of pencils? Use 3.14 for π and round to the nearest tenth.(1 point) cm2
Given:
Diameter (d) = 0.5 cm
Radius (r) = 0.25 cm (half of the diameter)
Height (h) = 19 cm
To find the surface area of the bundle of pencils, we use the formula for the surface area of a cylinder:
Surface Area = 2πrh + 2πr²
Substitute the values:
Surface Area = 2 * 3.14 * 0.25 * 19 + 2 * 3.14 * 0.25²
Surface Area = 2 * 3.14 * 0.25 * 19 + 2 * 3.14 * 0.0625
Surface Area = 2 * 3.14 * 4.75 + 2 * 3.14 * 0.0625
Surface Area = 29.84 + 0.39
Surface Area = 30.23 cm²
Therefore, the surface area of Ming's bundle of pencils is approximately 30.2 cm².