Joseph has a rain barrel in the shape of a cylinder with a height of 48 inches and a diameter of 24 inches. What is the surface area of the rain barrel? Use 3.14 for π and round to the nearest tenth.
wrong bot try again
bro get it correct
To find the surface area of the rain barrel, we need to find the lateral surface area of the cylinder and add the surface areas of the two circular bases.
1. Lateral surface area of the cylinder:
Lateral surface area = height x circumference of the base
Lateral surface area = 48 inches x (π x diameter)
Lateral surface area = 48 inches x (3.14 x 24 inches)
Lateral surface area = 48 inches x 75.36 inches
Lateral surface area = 3622.08 square inches
2. Surface area of one circular base:
Area of a circle = π x radius^2
Radius = diameter / 2 = 24 inches / 2 = 12 inches
Area of one base = 3.14 x (12 inches)^2
Area of one base = 3.14 x 144 square inches
Area of one base = 452.16 square inches
3. Total surface area:
Total surface area = Lateral surface area + 2 x Surface area of one base
Total surface area = 3622.08 square inches + 2 x 452.16 square inches
Total surface area = 3622.08 square inches + 904.32 square inches
Total surface area = 4526.4 square inches
Therefore, the surface area of the rain barrel is approximately 4526.4 square inches.
I apologize for the mistake. Let's correct the calculation:
1. Lateral surface area of the cylinder:
Lateral surface area = height x circumference of the base
Lateral surface area = 48 inches x (π x diameter)
Lateral surface area = 48 inches x (3.14 x 24 inches)
Lateral surface area = 48 inches x 75.36 inches
Lateral surface area = 3628.8 square inches
2. Surface area of one circular base:
Radius = diameter / 2 = 12 inches
Area of one base = π x (12 inches)^2
Area of one base = 3.14 x 144 square inches
Area of one base = 452.16 square inches
3. Total surface area:
Total surface area = Lateral surface area + 2 x Surface area of one base
Total surface area = 3628.8 square inches + 2 x 452.16 square inches
Total surface area = 3628.8 square inches + 904.32 square inches
Total surface area = 4533.12 square inches
Therefore, the surface area of the rain barrel is approximately 4533.1 square inches.
Let's calculate the surface area of the rain barrel correctly:
1. Lateral surface area of the cylinder:
Lateral surface area = height x circumference of the base
Lateral surface area = 48 inches x (π x diameter)
Lateral surface area = 48 inches x (3.14 x 24 inches)
Lateral surface area = 48 inches x 75.36 inches
Lateral surface area = 3628.8 square inches
2. Surface area of one circular base:
Radius = diameter / 2 = 24 inches / 2 = 12 inches
Area of one base = π x (12 inches)^2
Area of one base = 3.14 x 144 square inches
Area of one base = 452.16 square inches
3. Total surface area:
Total surface area = Lateral surface area + 2 x Surface area of one base
Total surface area = 3628.8 square inches + 2 x 452.16 square inches
Total surface area = 3628.8 square inches + 904.32 square inches
Total surface area = 4533.12 square inches
Therefore, the surface area of the rain barrel is approximately 4533.1 square inches. Thank you for your patience, and I hope this answer is correct this time.