A mixture of A and B occupying volume of 300cm3 and 100cm3 respectively exact a total pressure of 800mmHg What's the partial pressure of B
Given that the total pressure is 800 mmHg and the partial pressure of A is (300/400) * 800 = 600 mmHg, we can calculate the partial pressure of B as:
Partial pressure of B = Total pressure - Partial pressure of A
Partial pressure of B = 800 - 600
Partial pressure of B = 200 mmHg
Therefore, the partial pressure of B is 200 mmHg.