A certain mass of gas occupies 150cm cube at an atmospheric pressure of 10⁵Nm–² what will be it's new pressure if the volume is reduced 100cm³, assuming there is no charge in temperature
According to Boyle's Law, the pressure of a gas is inversely proportional to its volume when the temperature is constant. This can be expressed mathematically as:
P1V1 = P2V2
Where:
P1 = Initial pressure
V1 = Initial volume
P2 = Final pressure
V2 = Final volume
Given:
P1 = 10^5 Nm^-2
V1 = 150 cm^3
V2 = 150 cm^3 - 100 cm^3 = 50 cm^3
Substitute these values into the equation:
10^5 * 150 = P2 * 50
Solve for P2:
P2 = (10^5 * 150) / 50
P2 = 300,000 Nm^-2
Therefore, the new pressure of the gas would be 300,000 Nm^-2 when the volume is reduced to 50 cm^3.