A mixture contains 5.00 g each of O2, N2, CO2, and Ne gas. Calculate the volume of this mixture at STP
To calculate the volume of the gas mixture at STP, we first need to determine the number of moles of each gas present in the mixture.
1. Find the number of moles of each gas:
The molar mass of O2 = 32 g/mol
Number of moles of O2 = 5.00 g / 32 g/mol = 0.1563 mol
The molar mass of N2 = 28 g/mol
Number of moles of N2 = 5.00 g / 28 g/mol = 0.1786 mol
The molar mass of CO2 = 44 g/mol
Number of moles of CO2 = 5.00 g / 44 g/mol = 0.1136 mol
The molar mass of Ne = 20 g/mol
Number of moles of Ne = 5.00 g / 20 g/mol = 0.250 mol
2. Calculate the total number of moles in the mixture:
Total moles = 0.1563 mol + 0.1786 mol + 0.1136 mol + 0.250 mol = 0.6985 mol
3. Calculate the volume of the gas mixture at STP:
At STP, the molar volume of a gas is 22.4 L/mol
Volume of the mixture = Total moles x Molar volume = 0.6985 mol x 22.4 L/mol ≈ 15.66 L
Therefore, the volume of the gas mixture containing 5.00 g each of O2, N2, CO2, and Ne gas at STP is approximately 15.66 liters.