Two students in bumper cars want to prove conservation of momentum. They collide their bumper cars. The first bumper car has a mass of 120 kg and w moving with a velocity of 4 ms before the collision and with a velocity of -2 m/s after the collision. The second bumper car has a mass of 90 kg and wi moving at a velocity of -5 ms before the collision. To prove conservation of momentum, what must the velocity of the second bumper car be after the collision? (1 point)
O 3.0 m/s
O 2.3 m/s
O 1.0 m/s
O 2.7 m/s
To prove conservation of momentum, we can use the formula:
m1v1 + m2v2 = m1u1 + m2u2
where:
m1 = mass of first bumper car = 120 kg
v1 = velocity of first bumper car after collision = -2 m/s
m2 = mass of second bumper car = 90 kg
v2 = velocity of second bumper car after collision (unknown)
u1 = velocity of first bumper car before collision = 4 m/s
u2 = velocity of second bumper car before collision = -5 m/s
Plugging in the values:
120*(-2) + 90(v2) = 120*4 + 90*(-5)
-240 + 90v2 = 480 - 450
-240 + 90v2 = 30
90v2 = 270
v2 = 270/90
v2 = 3.0 m/s
Therefore, the velocity of the second bumper car after the collision to prove conservation of momentum must be 3.0 m/s.
The correct answer is: 3.0 m/s