A bowling ball is traveling at 7.6 meters per second when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
KE= 1/2 mv^2
(1 point)
Responses
22.8 J
22.8 J
693.12 J
693.12 J
173.28 J
173.28 J
346.65 J
The correct answer is 173.28 J.
Using the formula for kinetic energy:
KE = 1/2 * m * v^2
Substituting the given values:
KE = 1/2 * 6 kg * (7.6 m/s)^2
= 1/2 * 6 kg * (57.76 m^2/s^2)
= 1/2 * 6 kg * 57.76 J
Simplifying:
KE = 173.28 J
Therefore, the bowling ball has 173.28 Joules of kinetic energy when it hits the pin.