A bowling ball is traveling at 7.6 meters per second when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
KE=12mv2
(1 point)
Responses
346.65 J
346.65 J
693.12 J
693.12 J
173.28 J
173.28 J
22.8 J
The correct answer is 346.65 J.
Using the formula for kinetic energy, KE = (1/2)mv^2, we can plug in the values given:
KE = (1/2) * 6 kg * (7.6 m/s)^2
= (1/2) * 6 kg * (57.76 m^2/s^2)
= 3 kg * 57.76 J
= 173.28 J
Therefore, the correct answer is 346.65 J.