A bowling ball is traveling at 7.6 meters per second when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
(1 point)
A) 346.65 J
B) 22.8 J
C) 173.28 J
D) 693.12 J
The formula for kinetic energy is: KE = (1/2)mv^2
Where:
KE = kinetic energy
m = mass
v = velocity
Plugging in the given values:
KE = (1/2)(6 kg)(7.6 m/s)^2
Solving the equation:
KE = (1/2)(6 kg)(57.76 m^2/s^2)
KE = (1/2)(346.56 kg*m^2/s^2)
KE = 173.28 J
So the bowling ball has 173.28 Joules of kinetic energy when it hits the pin.
Therefore, the correct answer is choice C) 173.28 J.