A bowling ball is traveling at 7.6 meters per second when it hits a pin. If the bowling ball has a mass of 6 kilograms, how much kinetic energy does it have when it hits the pin?
KE=12mv2
(1 point)
Responses
22.8 J
22.8 J
173.28 J
173.28 J
693.12 J
693.12 J
346.65 J
346.65 J
To calculate the kinetic energy of the bowling ball, we can use the formula KE = 1/2 * mass * velocity^2.
Plugging in the values given:
KE = 1/2 * 6 kg * (7.6 m/s)^2
Squaring the velocity:
KE = 1/2 * 6 kg * 57.76 m^2/s^2
Multiplying the values:
KE = 28.88 kg m^2/s^2
Simplifying the units:
KE = 28.88 Joules
Therefore, the kinetic energy of the bowling ball when it hits the pin is approximately 28.88 Joules.
The closest answer choice is 22.8 J, but the correct answer is 28.88 J.