Use the equation of motion to answer the question.
x=x0+v0t+12at2
An object has a starting position of x = 2 m, a starting velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s?
(1 point)
Responses
11 m
9 m
18 m
5.5 m
Using the equation of motion, we can substitute the given values into the equation to find the final position after 2 seconds:
x = x0 + v0t + ½at^2
Given:
x0 = 2 m
v0 = 4.5 m/s
a = 0 (no acceleration)
t = 2 s
Plugging in the values:
x = 2 + 4.5(2) + ½(0)(2^2)
x = 2 + 9 + 0
x = 11
Therefore, the final position of the object after 2 seconds is 11 m.