x=x0+v0t+12at2
An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?
(1 point)
Responses
17 m
17 m
60 m
60 m
32 m
32 m
30 m
To find the final position of the object after 1 second, we can use the equation:
x = x0 + v0t + 1/2at^2
Given:
x0 = 2 m
v0 = 15 m/s
t = 1 s
a = 0 (constant speed)
Plugging in the values:
x = 2 + (15)(1) + 1/2(0)(1)^2
Simplifying:
x = 2 + 15 + (0)(1)
x = 2 + 15 + 0
x = 17 m
Therefore, the final position of the object after 1 second is 17 m.